When one atom of hydrogen (h) combines with one atom of bromine (br), their bonding results in a molecule of hbr. which of the following describes the arrangement of valence electrons in a bond between h and br? the valence electrons are shared equally between h and br. the valence electrons spend more time around the atom of h. the valence electrons spend more time around the atom of br. the valence electrons are given up by the h and gained by the br.

HBr is considered to be an ionic compound

So here Hydrogen loses its electron and this electron is being gained by bromine atom

In this process Hydrogen becomes positively charged while bromine becomes negatively charged

The two charges are attracted by electrostatic attractions

Thus the correct answer is

The valence electrons are given up by the H and gained by the Br.

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.