Chemistry, 17.07.2019 13:40 22ksotoq

What are the relative numbers of h3o+ and oh- ions in an acidic and alkaline and a neutral solution?

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Answer from: palafox9898

Explanation:

When a solution is acidic in nature then it means its pH range is from 1 to 6.9. And, in an acidic solution there are more number of hydrogen ( $H^{+}$ ) or hydronium ( $H_{3}O^{+}$ ) ions as compared to hydroxide ions ( $OH^{-}$ ).

For acidic solutions, $[H^{+}] or [H_{3}O^{+}]$ > $[OH^{-}]$

Whereas if a solution is neutral in nature then its pH will be equal to 7. This means that concentration of hydrogen ions will be equal to concentration of hydroxide ions.

For neutral solutions, $[H^{+}] or [H_{3}O^{+}]$ = $[OH^{-}]$

If a solution is basic in nature then its pH will be greater than 7. This means that in a basic solution concentration of hydroxide ions is more than the concentration of hydrogen ions.

For basic solutions, $[H^{+}] or [H_{3}O^{+}]$ < $[OH^{-}]$

Answer from: Quest

plants need sunlight, water, and carbon dioxide to make food. plants use the raw materials of water, nutrients they absorb from soil, and carbon dioxide to make sugars the plant can use. energy from the sun and chlorophyll are also needed.

Answer from: Quest

assuming that your periodic table has eighteen columns, you should highlight the four elements in the third column from the left of the table.

explanation

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the $3d$ have energy higher than those in the $4 s$ orbital while lower than those of the $4 p$ orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the $4s$ orbital is therefore filled right after $3p$ orbitals and before $3 d$ orbitals.

potassium has electron configuration $[\text{ar}] 4 s^{1}$ and calcium $[\text{ar}] 4 s^{2}$ . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration $[\text{ar}] 4 s^{2} \; 3d^{1}$ and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the $ns^{2} \; (n-1) p^{1}$ and should be highlighted as well.

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