Determine the enthalpy for this reaction: mgcl2(s)+2naoh(aq)→mg(oh)2(s)+2nacl (aq) express your answer in kilojoules per mole to one decimal place.

Given reaction:

MgCl2(s) + 2NaOH(aq) → Mg(OH)2(s) + 2NaCl(aq)

Formula:

ΔH°rxn = ∑nΔH°f(products) - ∑nΔH°f(reactants)

           = [ΔH°f(Mg(OH)2) + 2ΔH°f(NaCl)] -[ΔH°f(Mg(Cl)2 + 2ΔH°f(NaOH)]

           = [-924.7+2(-407.2)] - [-641.6+2(-470.1)] = -157.3 kJ/mol

Ans: Enthalpy for the reaction is -157.3 kJ/mol