Calculate the volume in liters required to prepare a 5.00 m solution of nacl using 15.4 g of nacl

52.7 ml First, determine how many moles of NaCl you have Atomic weight sodium = 22.989769 Atomic weight chlorine = 35.453 Molar mass NaCl = 22.989769 + 35.453 = 58.442769 g/mol Moles NaCl = 15.4 g / 58.442769 g/mol = 0.263505653 mol Now molarity is defined as moles/liter, so let's set up an equation for the number of liters we can make. molarity = moles/liter Substitute the known values 5.00 = 0.263505653/liter And solve for liters 5.00 = 0.263505653/liter 5.00* liter = 0.263505653 liter = 0.263505653/5.00 liter = 0.052701131 So you can make 0.0527 liters of the solution. Or 52.7 ml

Ch4 is nonpolar and insoluble in water. since all of the hydrogen atoms are evenly spread around the carbon atom even through the c h bond is polar all the poles cancel each other out.