How many grams of iodine needs to be added to 950 ml of carbon tetrachloride to make a 0.75 m solution? iodine 4.93 density (g/ml) 253.8 molecular weight (g/mol) carbon tetrachloride 1.594 density (g/ml) 153.8 molecular weight (g/mol)

The unit "m" in this given is used to refer to molality which is equal to the number of moles of the solute divided by the mass in kg of the solvent. If we let x be the mass of iodine, the equation for molality then becomes,

    molality = (x / 253.8) / ((950 mL)(1.594 g/mL)(1 kg/ 1000 kg)

    0.75 = (x / 253.8) / 1.5143

The value of x 288.247 g

288.25 g

It will fall off and tip over.