How many grams of water can be produced when 65.5 grams of sodium hydroxide reacts with excess sulfuric acid? unbalanced equation: h2so4 + naoh → h2o + na2so4 show all work to get final answer.

The balanced reaction that describes the reaction between sulfuric and sodium hydroxide to produce sodium sulfate and water is expressed H2SO4 + 2NaOH → 2H2O + Na2SO4. When 65.5 grams of sodium hydroxide reacts with excess sulfur, we need first to convert the mass to moles and multiply by stoich ratio 2/2 or 1. Hence the moles is multiplied to the molar mass of water. The final answer is 29.475 grams water.

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