Aphoton has a frequency of 2.9 × 10–16 hz. planck’s constant is 6.63 × 10–34 j•s. the energy of the photon, to the nearest tenths place, × 10–49 j.

Ans: E = 1.9 *10⁻⁴⁹ J

Given:

Frequency of photon, ν = 2.9 *10⁻¹⁶ Hz

planck's constant, h = 6.63*10⁻³⁴ Js

To determine:

The energy (E) of photon

Explanation:

Energy is related to the frequency by:

E = hν

   = 6.63*10⁻³⁴ Js * 2.9 *10⁻¹⁶ s-1

   = 1.9 *10⁻⁴⁹ J

wher is the rest of the question

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.