Express ksp in terms of molar solubility, x, for a salt with a formula of ab(s) ab2(s) ab3(s) a3b2(s)

See explanation below

Explanation:

The previous answer is wrong. To do this, we need to write the equilibrium equation for each species there, and then, write the Ksp in terms of molar solubility.

Molar solubility will be called as "x". So let's write the chemical equation for each species:

a) AB(s)

In this case, the equation would be:

AB(s) <> A(aq) + B(aq)

Doing an ICE chart we have:

        AB(s) <> A + B

I:                             0    0

C:                           +x   +x

E:                            x     x

In this case Ksp would be:

Ksp = [A] [B]

However, A and B are X so:

Ksp = x * x

Ksp = x²

This is the Ksp in terms of molar solubility for AB(s)

b) AB2(s)

In this case, we have two atoms of B so equation would be like this:

AB2(s) <> A(aq) + 2B(aq)

ICE chart:

          AB2(s) <> A(aq) + 2B(aq)

I:                                   0           0

C:                                 +x         +2x

E:                                  x           2x

Therefore Ksp:

Ksp = [A] [B]² ---> replacing with x:

Ksp = x * (2x)²

Ksp = x * 4x²

Ksp = 4x³

c) AB3(s)

We do the same as we did in part b, but changing concentration of B:

        AB3(s) <> A(aq) + 3B(aq)

I:                                   0           0

C:                                 +x         +3x

E:                                  x           3x

Therefore Ksp:

Ksp = [A] [B]³ ---> replacing with x:

Ksp = x * (3x)³

Ksp = x * 27x³

Ksp = 27x⁴

d) A3B2

We do the same, but changing concentration of A and B:

        A3B2(s) <> 3A(aq) + 2B(aq)

I:                                   0           0

C:                                +3x         +2x

E:                                  3x           2x

Therefore Ksp:

Ksp = [A]³ [B]² ---> replacing with x:

Ksp = (3x)³ * (2x)²

Ksp = 27x³ * 4x²

Ksp = 108x⁵

And that's all the ways of expressing the Ksp

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !