Chemistry, 22.07.2019 18:00 israel8471

Achemist wants to make 6.0 l of a 0.260 m cacl2 solution. part a what mass of cacl2 (in g) should the chemist use?

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In order to solve this problem the formula for molarity has to be revisited. The formula for molarity is M=(mole/volume). We are given the volume which is 6.0 L and the molarity of the solution of CaCl2 is 0.260 M. So, rearranging the molarity formula we can solve for the amount of moles in the 6.0 L solution of CaCl2 (0.260M * 6.0L = 1.56 mol CaCl2). Now using stoichiometry the we can find the grams of CaCl2 needed to make this solution. (1.56mol CaCl2) * (110.984 g / 1 mol CaCl2) = 173.135 g CaCl2 . So with the stoichiometric calculation we found that 173.153 g of CaCl2 are needed. Then following significant figures we can conclude that we need 173. g CaCl2.

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when atmosphere interacts with biosphere they focuses on on the sources and sinks of green house gases (ghgs) air pollutants, particular matters, water and energy between the earth's surface and the atmosphere. the biosphere affects the climate. the atmosphere and biosphere are in constant interaction with each other, and all living things rely on gases in the atmosphere for life. organisms such as animals take in oxygen gas form the atmosphere to use in every cell of their body for smooth functioning of daily routine exercises.

What happens when the atmosphere interacts with biosphere

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the balanced equation for reaction of ca metal with o2 to produce cao is as below

2 ca+ o2→ 2 cao2

explanation

the reaction is balanced since the number of atoms in reactant side is equal to number of atoms in product side. for example they are 2 atom of ca in reactant side and 2 atoms of ca in the product side.

the process is a meet the requirement of redox reaction because : calcium is oxidized from oxidation state 0 to 2+ while oxygen is reduced from oxidation state 0 to 2-

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Achemist wants to make 6.0 l of a 0.260 m cacl2 solution. part a what mass of cacl2 (in g) should th...