Chemistry, 23.07.2019 02:40 amypeace1978

Two types of reactions occur when baking soda and vinegar combine. the first is a double replacement reaction. write a balanced equation for this reaction. balance both equations. na(hco₃) + h(c2h₃o₂) → na(c₂h₃o₂) + h₂co₃ h₂co₃ → h₂o + __co₂

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The chemical equation for the Vinegar & Baking Soda reaction is: NaHCO3(s) + CH3COOH(l) â†’ CO2(g) + H2O(l) + Na+(aq) + CH3COO-(aq) with s = solid, l = liquid, g = gas, aq = aqueous or in water solution Another reaction is: NaHCO3 + HC2H3O2 â†’ NaC2H3O2 + H2O + CO2 The chemical reaction actually occurs in two steps. First, there is double displacement reaction in which acetic acid in vinegar reacts with sodium bicarbonate to form sodium acetate and carbonic acid: NaHCO3 + HC2H3O2 â†’ NaC2H3O2 + H2CO3 Then,Carbonic acid is unstable and undergoes a decomposition reaction to produce the carbon dioxide gas: H2CO3 â†’ H2O + CO2

Answer from: cheycheybabygirl01

1) Balanced chemical reaction:

1Na(HCO₃) + 1H(C2H₃O₂) → 1Na(C₂H₃O₂) + 1H₂CO₃.

Double replacement reactions (double displacement or metathesis reactions), two ionic compounds are exchanged, making two new compounds.

2) Balanced chemical reaction: 1H₂CO₃ → 1CO₂ + 1H₂O.

H₂CO₃ is carbonic acid.

CO₂ is carbon (IV) oxide or carbon dioxide.

Chemical decomposition is the separation of a single chemical compound (in this example carbonic acid) into its two or more simpler compounds (in this example water and carbon dioxide).

Answer from: Quest

answer: e. sour taste

explanation: acids are those substances which dissociates in water to give $h^+$ ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. acids are sour in taste. example: hcl

$hcl\rightarrow h^++cl^-$

bases are those substances which dissociates in water to give $oh^-$ ions or accepts $h^+$ ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. bases are bitter in taste. bases are slippery in nature.

$naoh\rightarrow na^++oh^-$

$nh_3+h^+\rightarrow nh_4^+$

Answer from: Quest

2b2t

explanation:

2b2t

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