Chemistry, 23.07.2019 05:10 lace64

Pf3i2 is a nonpolar molecule. based on this information, determine the f−p−f bond angle, the i−p−i bond angle, and the f−p−i bond angle

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The nonpolar molecule is with an electrostatic potential that is spherically symmetric if averaged across time, since electrons fluctuate, temporary dipoles exist anywhere at a given instant in a nonpolar molecule.

$\to \bold{F-P-F}$ bond angle is $\bold{120^{\circ}}$

$\to \bold{Cl-P-Cl}$ bond angle is $\bold{180^{\circ}}$

$\to \bold{F-P-Cl }$ bond angle is $\bold{90^{\circ}}$

Its combination is made up of a mixture bound together by chemical bonds & arranged in such a way that the arrangement of charge is symmetrical. The Nonpolar substances lack polarity. In a solution, they will not transform into ions.When certain bond angles occur in molecules, its net dipole moment cancels out and the molecule becomes non-polar.

Therefore, the angle is " $\bold{120^{\circ}}$ , $\bold{180^{\circ}}$ , and $\bold{90^{\circ}}$ ".

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Answer from: gugu1004

PF3I2 is a trigonal bipyramidal molecule whose image is shown in the answer below.

The molecule PF3I2 is trigonal bipyramidal. A trigonal pyramidal molecule has two axial bonds and three equatorial bonds. The two iodine atoms are positioned at axial positions while the fluorine atoms are positioned at equatorial positions.

The molecule is nonpolar because the individual dipoles due to fluorine and iodine atoms cancel out. Looking at the structure of the molecule;

The F - P - F bond angle is 120°The I - P - I bond angle is 180°The I - P - F bond angle is 90°

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Pf3i2 is a nonpolar molecule. based on this information, determine the f−p−f bond angle, the i−p−i b

Answer from: Quest

Compound with sulfer is bright red

Answer from: Quest

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 : $4x (s) + 3o_{2} (g) \rightarrow 2x_{2}o_{3} (s) h rxn = -600 kj/mol$

equation 2 : $2x (s) + 3cl_{2} (g) \rightarrow 2xcl_{3} (s) h rxn = -800 kj/mol$

equation 3 : $4xcl_{3} (s) + 3o_{2} (g) \rightarrow 2x_{2}o_{3} (s) + 6cl_(2} h rxn = -200 kj/mol$

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 : $4xcl_{3} (s) \rightarrow 4x (s) + 6cl_{2} ( h rxn = (+800) \times 2 kj/mol$

let us add equation 1 & 4

$4x (s) + 3o_{2} (g) \rightarrow 2x_{2}o_{3} (s) h rxn = -600 kj/mol$

$4xcl_{3} (s) \rightarrow 4x (s) + 6cl_{2} ( h rxn = (+1600) kj/mol$

$4xcl_{3} )s) + 3o_{2} \rightarrow 2x_{2}o_{3} (s) + 6cl_{2} (g) h rxn = (+1000) kj/mol$

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

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Pf3i2 is a nonpolar molecule. based on this information, determine the f−p−f bond angle, the i−p−i b...

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