Calculate the freezing point of a 2.00 molal solution of the nonelectrolyte glucose. the freezing point constant for water is 1.86 °c/molal.

Answer : The freezing point of the solution is,

Explanation :  Given,

Molality of the solution = 2.00 m

Formula used :  

where,

= change in freezing point

= temperature of pure water =

= temperature of solution = ?

i = Van't Hoff factor for non-electrolyte solution = 1

= freezing point constant =

m = molality  = 2.00 m

Now put all the given values in this formula, we get:

Therefore, the freezing point of the solution is,

state the principle of separating two immiscible liquids by separating funnel. describe an activity with diagram to separate a mixture of water and kerosene oil. answer: immiscible layers separate out in layers depending on their densities in separating funne

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6