Suppose you titrate 80.0 ml of 2.00 m naoh with 20.0 ml of 4.00 m hcl. what is the final concentration of oh− ions.

The final concentration of is 0.8 M.

Explanation:

0.06 moles of NaOH will give 0.06 moles of

0.08 moles of HCl will give 0.08 moles of

0.08 moles of will react with 0.08 moles of and (0.16-0.08)= 0.08 moles of will be left in 100 ml of solution.

Thus Molarity of

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.