2naclo3 --> 2 nacl + 3 o2 in order to produce 6 moles of oxygen gas, how many moles of sodium chlorate are required? round final answers to the tenth position, one place after the decimal. only report the numerical answer.

Answer : The number of moles of sodium chlorate required are, 4 moles

Solution : Given,

Moles of oxygen gas = 6 moles

The given balanced reaction is,

From the given balanced reaction, we conclude that

As, 3 moles of oxygen gas produces from 2 moles of sodium chlorate

So, 6 moles of oxygen gas produces from moles of sodium chlorate

Therefore, the number of moles of sodium chlorate required are, 4 moles