How many bromine atoms are present in 35.2 g of ch2br2?

2.44*10²³ Br atoms.

Explanation:

To solve this problem we need to calculate the number of moles of CH₂Br₂ in 35.2 g.

35.2 g / 173.8 g·mol⁻¹ = 0.2025 mol CH₂Br₂

Now we use Avogadro's number to calculate the number of Br atoms in 0.2025 moles of CH₂Br₂, keeping in mind that there are 2 Br atoms for each CH₂Br₂ molecule:

0.2025 mol CH₂Br₂  * 2.44*10²³ Br atoms

alienation, transformation, consumption, and the relativity of truth.

you can choose any one of these, they are all important themes.

these themes reflect the distinct sensibilities of both the modernist and postmodern aesthetic movements. (from google, you should paraphrase)

hope this !

- melanie

c. because step up transformer steps up the input voltage i.e increases the input voltage  

the number of turns are greater on the secondary side of step up transformer  

transformer does not handle dc current