How many moles of oxygen (o2) are present in 33.6 l of the gas at 1 atm and 0°c?

1.500 moles of O₂

Explanation:

At the pressure of 1 atm, the gas can be considered an ideal gas, so we can use the ideal gas equation:

PV = nRT

Where P is the pressure in atm, V is the gas volume in L, n is the number of moles, R is the gas constant = 0.082 atm.L/mol.K, and T is the temperature in K, so T = 0ºC + 273.15 = 273.15 K.

1x33.6 = nx0.082x273.15

22.3893n = 33.6

n = 1.500 moles of O₂

uranium-238 i believe is your answer

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.