Consider the reaction zn + no− 3 → nh3 + zn(oh)2− 4 carried out in an aqueous basic solution. when the equation is properly balanced, what is the total charge on the product side of the equation?

Oxidation half-reaction: Zn  + 4 OH⁻ → Zn(OH)₄²⁻ + 2 e-  

Reduction half-reaction: NO₃⁻ + 6 H₂O + 8 e-→ NH₃ + 9 OH⁻

Adding both reaction, we get the overall complete balanced equation:

4Zn + NO₃⁻ + 6 H₂O + 7 OH⁻  → 4 Zn(OH)₄²⁻ + NH₃

Thus, the charge in the product side is 4*-2 = -8.

so she was walking and she stepped on warm jeffy , uh uh uhh dadye i just pooped my pants

the maximum mass of nh3 is nh3 in grams