An aqueous solution of a soluble compound (a nonelectrolyte) is prepared by dissolving 33.2 g of the compound in sufficient water to form 250 ml of solution. the solution has an osmotic pressure of 1.2 atm at 25 °c. what is the molar mass (g/mole) of the compound?

Answer : The molar mass (g/mole) of the compound is, 2707.55 g/mole

Solution : Given,

Mass of solute = 33.2 g

Volume of solution = 250 ml = 0.250 L

Temperature of solution =

Formula used for osmotic pressure :

where,

= osmotic pressure

V = volume of solution

R = solution constant  = 0.0821 L.atm/mole.K

T= temperature of solution

M = molar mass of solute

w = mass of solute

Now put all the given values in the above formula, we get the molar mass of the compound.

Therefore, the molar mass (g/mole) of the compound is, 2707.55 g/mole