21 pts. sodium reacts with oxygen to produce sodium oxide as described by the balanced equation below. if 54.1g of sodium reacts with excess oxygen gas to produce 61.8g of sodium oxide, what is the percent yield? show all work. (hint: be sure to calculate theoretical yield first) 4na + o2  -->   2na2o

First, calculate the amount fo Na2O that should be produced with the given amount of sodium using proper dimensional analysis and  the balanced chemical reaction,

   theoretical amount of Na2O = (54.1 g of Na)(1 mol Na/23 g Na)(2 mos Na2O/4 mols Na)(62 g Na2O/ 1mol Na2O)
       
      theoretical amount of Na2O = 72.9 g of Na2O

Calculation of percent yield,

                % yield = (61.8 g Na2O) / (72.9 g of Na2O) x 100%
                 % yield = 84.75%

84.75%

What does that mean you dum bum