Sulfur reacts with oxygen to produce sulfur trioxide gas. balance the equation. __s+) > __so(sub3)

2S + 3O2 ==> 2SO3  
Let's start off with the unbalanced equation and count atoms of each element on both sides of the arrow.  
S + O2 ==> SO3  
There's 1 sulfur atom on both sides which is good. However, there's 2 oxygen atoms on the left and 3 on the right. So calculate the Least common multiple (LCM) of 2 and 3 which is 6. And adjust the coefficients on both sides to have 6 oxygen atoms on each side, giving: 
S + 3O2 ==> 2SO3  
Now we have 6 oxygen atoms on each side which is good, but there's only 1 sulfur atom on the left and 2 on the right. Since the LCM of 1 and 2 is 2, all we need to do is adjust the coefficient on the left to get 2 sulfur atoms there. So:
 2S + 3O2 ==> 2SO3  
We now have 2 sulfur atoms on each side of the equation and 6 oxygen atoms on each side, so the resulting equation is balanced.

1. and 2. question: in which equation? or i don't understand you, 3. a), 4. c), 5. c), 6. b), 7. d), 8. d) if small number is underlined(behind symbol) , b) if big number is underlined(in front of symbol)9. what is underlined there? 10. c)