What mass of o2, in grams, is required to completely react with 0.025 g c3h8?

0.091

Explanation:

the balanced chemical equation for the reaction is as follows;

C₃H₈ + 5O₂ ---> 3CO₂ + 4H₂O

stoichiometry of C₃H₈ to O₂ is 1:5

number of moles of C₃H₈ reacted - 0.025 g / 44.1 g/mol = 0.000567 mol according to molar ratio of 1:5

number of O₂ moles required are 5 times the amount of C₃H₈ moles reacted therefore number of O₂ moles required - 0.000567 x 5 = 0.00284 mol .

mass of O₂ required - 0.00284 mol x 32.00 g/mol = 0.091 mol .

answer is 0.091 mol

the answer is 1 i believe

the correct answer to this question is 2