Quickly but you are asked to make 112 g of iron from iron oxide and excess carbon monoxide. fe2o3 (s) + 3co (g) → 2fe (l) + 3co2 (g) approximately how many grams of iron oxide must you use? question 5 options: a. 720 g b. 240 g c. 107 g d. 160 g

Calculate  the number of   moles  of  moles  of  iron  prepared
mole=  mass/RFM
RFM   of  iron  is =56  g/  mol
moles  of  iron prepared  is  therefore   112g /56g/mol=2moles
by  use  of  reacting  ratio between Fe2O3 to  Fe  that  is  1:2  therefore  moles of  Fe2O3  used  is  (1x2)/2+1 mole
mass  of  Fe2O3=RFM  x number  of  moles
RFM of Fe2O3=160g/mol
mass= 1 mole  x 160 g/.mol=160g (D)

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