A50 l cylinder is filled with argon gas to a pressure of 10130.0 kpa at 300°c. how many moles of argon gas does the cylinder contain? (given: r = 8.314 l∙kpa/k∙mol) 2519.142 mol

To answer this question, we will use the general gas law which states that:
PV = nRT where:
P is the pressure of the gas = 10130.0 kPa
V is the volume of the gas = 50 liters
n is the number of moles that we want to calculate
R is the gas constant = 8.314 L∙kPa/K∙mol
T is the temperature = 300+273 = 573 degree kelvin

Substitute with the givens in the equation to get the number of moles as follows:
10130 * 50 = n * 8.314 * 573
506500 = 4763.922 n
n = 506500 / 4763.922
n = 106.3199 moles

The answer is c. 320 g