Match the term with its description. match term definition colloid a) a mixture in which two or more liquids are mixed that normally are not mixable emulsion b) mixture that has its different components mixed evenly within the substance heterogeneous c) a mixture in which microscopically insoluble particles are suspended throughout another substance homogeneous d) mixture that has its different components mixed unevenly within the substance

Colloid :A mixture in which microscopically insoluble particles are suspended throughout another substance

Emulsion: A mixture in which two or more liquids are mixed that normally are not mixable

Heterogeneous : Mixture that has its different components mixed unevenly within the substance

Homogeneous : Mixture that has its different components mixed evenly within the substance

Explanation:

Colloids are solutions in which small sized particles are suspended throughout the solution as they do not settle own their own. Example: Blood

Emulsion : is a mixture of two liquids that normally do not mix. Example: Oil in water

Heterogeneous mixtures  : It is a mixture that has non-uniform  composition throughout the solution and the particle size or shapes are also different.  Example: sand in water

Homogeneous mixtures  : It is a mixture that has uniform composition throughout the solution and the particle size or shapes are not different.  Example: Sugar in water

1. the question asks the most appropriate, which seems to rule out "all of the above." your choice appears to be the correct one.

2. the protocol described is good for identifying correlation, but not cause and effect. for cause/effect, you need to devise a protocol that will assign the treatment (or not) to groups that have essentially the same "demographics" with respect to all the other variables. your choice regarding control group seems appropriate. random assignment of treatment (choice d) may be appropriate also. (i think you can argue that b and d are just different descriptions of the same method.)

3. d will randomize the birds, but may not guarantee there are 10 in each group. e will do both, so seems the better choice.

comment on question 2

based on the problem statement, it seems clear that confident, attentive drivers are more likely to use daytime running lights. so, the protocol might need to be devised in such a way that the lights would be turned on or off without the driver's knowledge. (an attentive driver will figure it out.) assigning a confident, attentive driver to a group required to drive without running lights might mess with his/her confidence and attentiveness. you don't want your experiment to do that. (nor do you want the experiment to subject a driver to greater risk of accident as a consequence of driving without running lights.) experiments involving human safety are always problematic.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml