How many protons, neutrons, and electrons are there in a neutral atom of 97tc (technetium-97)?

Protons = Electrons = 43

Neutrons = 54

Explanation:

Technetium is transition metal and belongs to the 5d-series in the periodic table. Tc- 97  has an atomic number Z = 43 and Atomic mass A = 97

For a neutral atom:

Atomic number = number of protons = number of electrons

Atomic mass = number of protons + neutrons

For Tc-97:

Z = 43, therefore

Protons = 43

Electrons = 43

A = 97

i.e. 97 = 43 - neutrons

# neutrons = 97 - 43 = 54

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be