Achemical reaction yields 2 moles of lithium hydroxide. how many grams of lithium hydroxide are present

We are tasked to solved for the grams of lithium hydroxide present in 2 moles of lithium hydroxide. In order to solve for the amount of lithium hyroxide in grams, we need the molecular formula of lithium hydroxide. Searching in the net, its molecular formula is 24 g/mol or simply,
Li=7 g/mol , O= 16 g/mol, H=1 g/mol
LIOH=7+13+1=24 g/mol

for every 2 mol of LIOH, we have LIOH in grams:
LIOH: 2mol x 24 g/mol= 48 g

Therefore, 48 g of Lithium hydroxide are present in the yield

What are the options? i can you if you give them.