The combustion of ammonia in the presence of excess oxygen yields no2 and h2o: 4 nh3 (g) + 7 o2 (g) â 4 no2 (g) + 6 h2o (g) the combustion of 28.8 g of ammonia consumes g of oxygen.

The answer would be 118.68 g.
Explanation for this is:4 moles of NH3 give 4 moles of NO2 
so 1mole of NH3 will give 1 mole of NO2 
43.9 grams of NH3 contains 2.58 moles 
so 2.58 moles will be produced of NO2 
which is 118.7 grams this the amount of oxygen that is used.

The answer options is d