During the combustion of 2.00 g of coal, the temperature of 500 g of water inside the calorimeter increased from 25.0°c to 43.7°c. the specific heat of water is 4.18 j/g·°c. how much heat did the reaction generate?

Answer is: 39,083kJ.
m(coal) = 2,00g.
m(water) = 500g.
ΔT = 43,7°C - 25°C = 18,7°C, difference at temperatures.
c(water) = 4,18 J/g·°C, specific heat of water
Q = m(water)·ΔT·c(water), heat of reaction.
Q = 500g·18,7°C·4,18J/g·°C.
Q = 39083J = 39,083kJ.

The answer is b i think

Ibelieve your answer is true