The artificial sweetener aspartame (nutra-sweet) formula c14h18n2o5 is used to sweeten diet foods, coffee and soft drinks. how many moles of aspartame are present in 225 g of aspartame?

Answer is: 0,765 moles of aspartame.
m(C₁₄H₁₈N₂O₅) = 225 g.
M(C₁₄H₁₈N₂O₅) = 14·12 + 18·1 + 2·14 + 5·16 = 294 g/mol.
n(C₁₄H₁₈N₂O₅) = m(C₁₄H₁₈N₂O₅) ÷ M(C₁₄H₁₈N₂O₅) = 225 g ÷ 294 g/mol.
n(C₁₄H₁₈N₂O₅) = 0,765 mol.
m - mass of aspartame.
M - molar mass of aspartame.
n - amount of substance of aspartame.

Ibelieve the answer 4 moles