A50.0 g gold spoon at 10.0 °c is placed in a cup of how water 95.0 °c. how much heat does the water lose to the spoon if the spoon reaches a temperature of 59.0 °c?

The water lost 313.6 J of heat to the spoon

Temperature is one of the principal quantities that shows the degree of heat or cold from an object / space

Temperature is used as a guide to the level of heat energy from objects

Temperature cannot be measured by the surface of the hand because it is not accurate but can be measured by a thermometer. Temperature units include Celsius, Fahrenheit, Reamur or Kelvin

Whereas heat is a form of energy that can flow from high-temperature objects to low-temperature objects.

So heat moves when there is a difference in temperature and can increase or decrease the temperature. An object that receives a lot of heat will cause a large increase in temperature

The amount of heat is influenced by the mass of the object and the difference in temperature

Can be formulated

Q = m.c.ΔT

Q: heat received or removed by an object (J)

m: object mass (kg)

c: heat type substance (J / kg⁰C)

ΔT: temperature change (⁰C)

When A 50.0 g of gold spoon at 10.0 ° c is placed in a cup of hot water 95.0 ° c. Heat balance occurs:

q lost = q gain

q lost from water = q gain from spoon

q lost from water = m. cp (gold). delta t

The specific heat of gold is 0.128 J / g ° C.

q lost from water = 50 g. 0.128. (59-10)

q lost from water = 313.6 J

heat and temperature

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grams of water

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decrease heat transfer between two objects

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Keywords: heat gain, heat lost

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explanation:

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