If 5400. joules of energy were supplied to 4.5 grams of ice at -10 degree celsius, how many grams of what phases would you have?

Answer is: 3,66 g of liquid water and 0,84 g of vapor.
1) Q₁ = m·C·ΔT
Q₁ = 4,5 g · 2,108 J/°C·g · 10°C.
Q₁ = 97,86 J heat required to warm the ice to 0°C.
2) Q₂ = 4,5 g · 334 J/g.
Q₂ = 1503 J heat required to melt the ice to water at 0°C.
3) Q₃ = 4,5 g · 4,184 J/°C·g · 100°C
Q₃ = 1882,28 J heat required to warm the water from 0°C to 100°C.
Q₄ = 5400 J - 3483,14 J = 1916,86 J heat left to vapourize the water.
m(vapor) = 1916,86 J ÷ 2257 J/g = 0,84 g.

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