This balanced chemical equation represents a chemical reaction: 6no + 4nh3 → 5n2 + 6h2o what volume of nh3 gas, at standard temperature and pressure (stp), is required to react with 15.0 g of no?

The answer is: volume of ammonia gas is 7.4 L.

Chemical reaction: 6NO + 4NH₃ → 5N₂ + 6H₂O.

m(NO) = 15 g; mass of nitrogen(II) oxide.

M(NO) = 30 g/mol; molar mass of nitrogen(II) oxide.

V(NH₃) = ?

n(NO) = 15 g ÷ 30 g/mol.

n(NO) = 0.5 mol; amount of nitrogen(II) oxide.

From chemical reaction: n(NO) : n(NH₃) = 6 : 4.

0.5 mol : n(NH₃) = 6 : 4.

n(NH₃) = 0.33 mol; amount of ammonia.

Vm = 22.4 L/mol; molar volume at STP.

V(NH₃) = 0.33 mol · 22.4 L/mol..

V(NH₃) = 7.4 L.

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.

the answer is barium and copper bromide