Iam currently doing the test and i need . the decomposition of calcium carbonate, caco3(s) --> cao(s) + co2(g), has the following values for free energy and enthalpy at 25.0°c. g = 130.5 kj/mol h = 178.3 kj/mol what is the entropy of the reaction? use g = h – ts. a. -160.3 j/(mol. k) b. -47.8 j/(mol. k) c. 160.3 j/(mol. k) d. 1,912 j/(mol. k)

There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. in the first step, calcium carbide and water react to form acetylene and calcium hydroxide: cac2 (s) + 2h2o (g) → c2h2 (g) + caoh2 (s) =δh−414.kj in the second step, acetylene, carbon dioxide and water react to form acrylic acid: 6c2h2 (g) + 3co2 (g) + 4h2o (g) → 5ch2chco2h (g) =δh132.kj calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide from these reactions. round your answer to the nearest kj .