Chloroform (chcl3), an important solvent, is produced by a reaction between methane and chlorine. ch4(g) + 3 cl2(g) chcl3(g) + 3 hcl(g) how many grams of ch4 is needed to produce 66.5 g chcl3?

CH4 +3Cl2 ---> CHCl3  + 3 HCl
   one   molecules  of  CH4  reacted  with  3  molecules  of  Cl  to  form one  molecule  of CHCl3  and  3  molecules  of  HCl

this  implies  that  the  ratio  of  CH4  to  CHCl3  is  1:1

the   moles of  CHCl3  formed=66.5/119.5(molar  mass  of  CHCl3) =0.556 moles
 since  ratio  is  1:1  the  moles  of  CH4  is  also  0.556moles
mass=moles  x  molar  mass
mass=0.556 x  16(molar  mass of  CH4)= 8.896grams