How many moles of c6h14 contain 9.25 × 1024 molecules of c6h14?

According to Avagadros law 1 mole of a substance contains 6.02 × 10^23 particles.
Thus, 1 mole of C6H14 contains 6.02 × 10^ 23 molecules,
Therefore, 9.25 × 10^24 molecules will have; 
      (9.25 × 10^24)/ (6.02 ×10^23) 
   =  15.365 moles.

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A. volume stays constant. just took took the quiz