What is the mass of the missing reactant in the following reactions, given that the reaction goes to completion? do not include units. - 2.7 g water + g carbon dioxide --> 9.3 g carbonic acid - 32.0 g sodium hydroxide + 16.0 g hydrofluoric acid --> g water + 33.6 g sodium fluoride - 0.60 g calcium carbonate + 0.48 g sodium hydroxide --> g sodium carbonate + 0.45 g calcium hydroxide - 0.53 g sodium hydroxide + 0.37 g carbon dioxide --> g sodium hydrogen carbonate

1)  2.7 g water + 6,6 g carbon dioxide → 9.3 g carbonic acid.
According to principle of mass conservation mass of reactants and products are the same after chemical reactio. 2,7 g + 6,6 g = 9,3 g.
2) 32.0 g sodium hydroxide + 16.0 g hydrofluoric acid --> 14,4 g water + 33.6 g sodium fluoride.
m(water) = 32 g + 16 g - 33,6 g.
3) 0.60 g calcium carbonate + 0.48 g sodium hydroxide --> 0,63 g sodium carbonate + 0.45 g calcium.
m(sodium carbonate) = 0,6 g + 0,48 g - 0,45 g.
4) 0.53 g sodium hydroxide + 0.37 g carbon dioxide --> 0,9 g sodium hydrogen carbonate.
m(sodium hydrogen carbonate) = 0,53 g + 0,37 g = 0,9 g.

For cyclohexane compounds drawn in a chair conformation:   -axial bonds are vertical  -equatorial bonds are parallel to two bonds within the ring.  thus, as i assume the chair conformation is drawn:   -the x group is in an axial position, as are the five other vertical bonds.  -three axial bonds are on the top face of the ring  -the other three axial bonds are on the bottom face  the position of the second substituent on each ring carbon is equatorial.  gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other.  drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1.  click this link and watch some academic videos that may you more understand the topic