note the ph and poh values labeled with letters on the ph scale below.

based on log rules and the way ph is calculated, what is the difference in [oh– ] concentration between point a and point b.

a) 10^1
b) 10^5
c) 10^6
d) 10^7

Answer is: the difference is c) 10^6.

1) pH (point A) = 1.

pH + pOH = 14.

pOH = 14 - 1.

pOH = 13.

pOH = -log[OH⁻] ⇒ [OH⁻] = 10∧(-pOH).

[OH⁻] = 10⁻¹³ M; concentration of hydroxide ions at point A.

2) pOH (point B) = 7.

[OH⁻] = 10⁻⁷ M; concentration of hydroxide ions at point B.

3) the difference in [OH⁻]: 10⁻⁷ M / 10⁻¹³ M = 10⁶.

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