15. a 22.4-l sample of which of the following substances, at stp, would contain 6.02 x 10^23 representative particles?   *a. goldb. sodium chloridec. sulfurd. carbon dioxide16. what information is needed to calculate the percent composition of a compound?   *a. the formula of the compound and the atomic mass of its elementsb. the formula of the compound and its volumec. the weight of the sample to be analyzed and its molar volumed. the weight of the sample to be analyzed and its state of matter

The answer for 15 is oxygen or carbon dioxide they are the same thing!

The answer for 16 is the formula of the compound and the atomic mas of its elements!

This is for if you take connections!

Answer :

Part 15 : Only gold contains number of particles.

Part 16 : The correct option is, (a) the formula of the compound and the atomic mass of its elements.

Explanation :

Part 15 :

As we know that, 1 mole of substance occupies 22.4 L volume of gas and 1 mole of substance contains number of particles.

So, 22.4 L volume of gas contains number of particles.

(a) Gold :

Gold contains number of particles.

(b) Sodium chloride (NaCl) :

In sodium chloride, there are 2 atoms. So, it contains number of particles.

(c) Sulfur (S₈) :

In sulfur, there are 8 atoms. So, it contains number of particles.

(d) Carbon dioxide (CO₂) :

In carbon dioxide, there are 3 atoms. So, it contains number of particles.

Hence, from this we conclude that only gold contains number of particles.

Part 16 :

Percent composition : It is calculated by dividing the mass of each element in one mole of the compound that means dividing the mass of each element by the total molar mass of the compound.

Formula used :

Hence, the information needed to calculate the percent composition of a compound is, the formula of the compound and the atomic mass of its elements.

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