The volume of a gas is 450 ml when its pressure is 1.00 atm. if the temperature of the gas does not change, what is the pressure when its volume is changed to 2.00 l? use mc004-1.jpg. 0.225 atm 0.444 atm 2.25 atm 4.44 atm

Ans: 0.225 atm

Given:

Initial volume of gas, V1 = 450 ml = 0.450 L

initial pressure, P1 = 1.00 atm

Final volume, V2 = 2.00 L

To determine:

Final pressure, P2

Explanation:

Based on ideal gas equation:

PV = nRT  (1)

where P = pressure, V = volume, n = # moles, R = gas constant, T = temp

Under constant, T and n, eq(1) can be expressed as:

PV = constant

(or) P1V1 = P2V2

P2 = P1V1/V2 = 1.00 atm * 0.450 L/2.00 L = 0.225 atm

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3