What would be the resulting molarity of a solution made by dissolving 31.3 grams of ca(oh)2 in enough water to make a 1059 milliliter solution

Molecular mass = 74.093
Number of moles in 31.3 g = 31.3/74.093 = 0.422442
Molarity when dissolved in 1059 mL
= 0.422442 / 1.059
= 0.3989 mol

The resulting molarity is 0.399 mol (to 3 significant figures)

Ithink is a because if say increased in electronegativity