Determine the melting point of an aqueous solution containing 101 mg of saccharin (c7h5o3ns) added to 1.00 ml of water (density of water = 1.00 g/ml, kf = 1.86°c/m).

Answer is:  the melting point of an aqueous solution is -1,023°C.
m(C₇H₅O₃NS) = 101 mg · 0,001 g/mg = 0,101 g.
V(H₂O) = 1,00 mL.
m(H₂O) = d(H₂O) · V(H₂O).
m(H₂O) = 1 g/mL · 1 mL = 1 g = 0,001 kg.
n(C₇H₅O₃NS) = 0,101 g ÷ 183,2 g/mol = 0,00055 mol.
b(C₇H₅O₃NS) = 0,00055 mol ÷ 0,001 kg = 0,55 mol/kg = 0,55 m.
ΔT = Kf · b(C₇H₅O₃NS).
ΔTsolution) = 1,86°C/m · 0,55 m = 1,023°C.