You only have 25 grams of iron iii phosphate in you lab unit. what is the maximum amount of iron iii sulfate that you can produce. fepo4+ naso4--> fe (so4) +na3po4.

In a chemical reaction, the amount of products is constrained by the limiting reagent. Here, we first need to balance the chemical equation. Then we convert the amount of iron(III) phosphate into moles, and multiply by the ratio set up by the stoichiometric coefficient of iron(III) sulfate to iron(III) phosphate. The answer is 0.00040 g of iron(III) sulfate.

I’m not sure what your trying to say here.. can you clarify again?