Ga2o3(s) + 3socl2(l) --> 2gacl3(s) +3so2 in a certain reaction, 71.8 g of ga2o3 is reacted with 110.8 g socl2.the gacl3 produced is collected and its mass founded to be 97.66 g. what is the theoretical yield of gacl3?

The balanced equation is;
Ga2O3 + 3 SOCl2 → 2GaCl3 + 3SO2
the no. of moles of Ga2O3 = Weight / Molecular weight
                                              = 71.8 / 187.44 = 0.383 moles >>> (1)
the no. of moles of SOCl2 = (Wt / M.wt) / 3 = (110.8/119)/3 = 0.310 moles >>> (2)
From (1) and (2), 
∴ SOCl2 determines the yield of the reaction (lower no. of moles)
∴ No. of moles of GaCl3 = 0.310 * 2 = 0.620 moles >>> (3)
∴ the theoritical yield (weight in gram) of GaCl3 = no. of moles * M.wt.
                                                                                = 0.620 * 176= 109.12 g