If 0.98 moles of bacl2 are dissolved in enough water to make a 1.2-liter solution, what is the resulting molarity? a. 0.55 m bacl2 b. 0.82 m bacl2 c. 1.2 m bacl2 d. 0.45 m bacl2

Correct Option B i.e. 0.82 M

Reason:
Given: number of moles of BaCl2 = 0.98, Volume of solution = 1.2 l

Molarity of solution = 
                               = 
                               = 0.82 M

 Thus, molarity of the solution is 0.82 M

The answer is B. 0.82 M BaCl2

How to generate the

Let:

n = amount of substance
V = volume of solution

Equation for n:

n (BaCl2) = 0.98 mol. (unit of mole)

Equation for V:

V (solution) = 1.2L

Required:

c(BaCl2) =?

Equation for the whole problem:

c(BaCl2) = n (BaCl2) / V (solution)

c(BaCl2) = 0.98 mol / 1.2L

c(BaCl2) = 0.82 mol/L

= 0.82 M

Thus,

the resulting molarity is 0.82 M BaCl2

Sorry i dont understand the question can you rephase it?