What is the volume, in ml, of 0.50 moles of ammonia (nh3) at stp? a. 1120 l b. 22.32 ml c. 8500 ml d. 11,200 ml

For the purpose we will here use the ideal gas law:

p×V=n×R×T

V= ?
n = 0.5 moleT= 273.15 K (at STP)
p= 101.325 kPa (at STP)
R is  universal gas constant, and its value is 8.314 J/mol×K

Now when we have all necessary date we can calculate the number of moles:
V=nxRxT/p
V=0.5x8.314x273.15/101.325= 11.2 L = 11200 mL

D.

English , i don't understand spanish.