If kp = 0.15, which statement is true of the reaction mixture before any reaction occurs?

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For the reaction N2O4(g) ⇄ 2NO2(g), a reaction mixture at a certain temperature initially contains both N2O4 and NO2 in their standard states (meaning they are gases with a pressure of 1 atm).  If Kp = 0.15, which statement is true of the reaction mixture before any reaction occurs?

(a) Q = K;   The reaction is at equilibrium.
(b) Q < K;   The reaction will proceed to the right.
(c) Q > K;   The reaction will proceed to the left.

The answer is the option (c) Q > K; The reaction will proceed to the left, since Qp = 1, and 1 > 0.15.
Explanation:

Kp is the equilibrium constant in term of the partial pressures of the gases.

Q is the reaction quotient. It is a measure of the progress of a chemical reaction.

The reaction quotient has the same form of the equilibrium constant but using the concentrations or partial pressures at any moment.

At equilibrium both Kp and Q are equal. Q = Kp

If Q < Kp then the reaction will go to the right (forward reaction) trying to reach the equilibrium,

If Q > Kp then the reaction will go to the left (reverse reaction) trying to reach the equilibrium.

Here, the state is that both pressures are 1 atm, so Q = (1)^2 / 1 = 1.

Since, Q = 1 and Kp = 0.15, Q > Kp and the reaction will proceed to the left.

The gas would begin to expand, and eventually the can would burst or explode.

The state or quality of being humid.a quantity representing the amount of water vapor in the atmosphere or a gas.