Asolution of water (kf=1.86 ∘c/m) and glucose freezes at − 2.75 ∘c. what is the molal concentration of glucose in this solution? assume that the freezing point of pure water is 0.00 ∘c.

Explanation:

Relation between freezing temperature and molal concentration is as follows.

The given data is as follows.

    = difference in temperature = =

            molality, (m) = ?  

Now, putting the given values into the above formula as follows.

                m =

                    =

                    = 1.48 m

Therefore, we can conclude that molal concentration of glucose in the given solution is 1.48 m.

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be