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Writing net ionic equation: a solution of diamminesilver(i) chloride is treated with dilute nitric acid. so what i did was.. [ag(nh3)2]cl(aq) + hno3(aq) -> the answer is [ag(nh3)2]+ + cl- + 2h+ -> agcl + 2nh4+ i would guess that the oxidation #s for diamminesilver(i) chloride would be: ag +1 nh3 0 cl -1 can someone show me the steps in between? i don't really know how to break the [ag(nh3)2]cl apart and predict/form the products.
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Writing net ionic equation: a solution of diamminesilver(i) chloride is treated with dilute nitric...
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