2. the electrolyte in automobile lead storage batteries is a 3.75 m sulfuric acid solution that has a density of 1.230 g/ml. calculate the mass percent, molality, and mol fraction of the sulfuric acid. i am so lost dont know how to get the kg of solvent,

Solutions:
1. 
Density of solution = (1.23 g / mL) • (1000 mL/ 1 L)
= 1230 g solution/L solution.

grams of H2SO4 = (3.75 mols H2SO4) • (98.07 g H2SO4 / 1 mol)
= 368 g H2SO4 in 1 L.

mass percentage H2SO4 = 368 g H2SO4 / 1230 g solution) • 100
= 29.9% H2SO4

2. Convert Grams to moles
= 368 g H2SO4 • (1 mol H2SO4/ 98.07 g H2SO4)
 = 3.75 mol H2SO4
difference of total solution- total grams=  1230 g solution - 368 g H2SO4
= 862 g H2O. 
Convert grams to kg,
= 862 g 8 (1 kg / 1000 g)
= 0.862 kg H2O
Thus,
Molality = m
= 3.75 mol H2SO4/ .862 kg H2O
= 4.35.

3. = 862 g water • (1 mole / 18 g water)
= 47.89 mol water
mole fraction of H2SO4 = X
= 3.75 mol H2SO4/ (3.75 moles H2SO4 + 47.89 moles water) 
 = 0.726