The reaction 2a → a2 was experimentally determined to be second order with a rate constant, k, equal to 0.0265 m–1min–1. if the initial concentration of a was 4.00 m, what was the concentration of a (in m) after 180.0 min?

The integrated rate law for a second-order reaction is given by:

where, [A]t= the concentration of A at time t,

[A]0= the concentration of A at time t=0

k = the rate constant for the reaction

Given: [A]0= 4 M, k = 0.0265 m–1min–1 and t = 180.0 min

Hence,

                                        = 4.858

Therefore, [A]t= 0.2058 M.

Concentration of A, after 180 min, is 0.2058 M

i had this on my unit activity, i can you if you are a plato student. are you a plato student?

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !